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How do I integrate and differentiate 1/(x^2)?

1/( x 2 ) can be written as x -2 We know that to differentiate you need to multiply by the value of the old power and minus 1 from it. This means dy/dx of y= x -2 is -2 x -3 =-2/(x 3 ) To integrate you add o...
JG
Answered by Judy G. Maths tutor
4691 Views

Let w, z be complex numbers. Show that |wz|=|w||z|, and using the fact that x=|x|e^{arg(x)i}, show further that arg(wz)=arg(w)+arg(z) where |.| is the absolute value and arg(.) is the angle (in polar coordinates). Hence, find all solutions to x^n=1 .

Put w=a+bi, z=c+di where a, b, c, d are real, and i 2 =-1. Then |wz| 2 =|(a+bi)(c+di)| 2 =|ac-bd+(ad+cb)i| 2 =(ac) 2 +(bd) 2 -2bcd+(ad) 2 +(cb) 2 +2abcd=(ac) 2 +(bd) 2 +(ad) 2 +(cb) 2 =(a 2 +b 2 )(c 2 +d 2 )...
JK
Answered by Jihoon K. Maths tutor
8304 Views

Express 9^(3x+)1 in the form 3^y giving y in the form of ax+b where a and b are constants.

Fistly show that: 9 3 x +1 =3 y To find x we need to get the left hand side of the equation to be 3 m (3 x +1) where 3 m =9. I know that 3 2 =9 (but if you don't you can use m=log 3 (9)=2) This gets us: 3 2(...
JG
Answered by Judy G. Maths tutor
6109 Views

What is the Product Rule?

The product rule is used when differentiating two functions that are multiplied by eachother. The formula for the product rule is: U (dv/dx) + V (du/dx) where 'dv/dx' is the differential of the function, V. ...
AW
Answered by Abbie W. Maths tutor
4119 Views

A curve has parametric equations x=t(t-1), y=4t/(1-t). The point S on the curve has parameter t=-1. Show that the tangent to the curve at S has equation x+3y+4=0.

To anwser this question we need to find a linear equation of the form y=mx+c which we can rearrange to give the desired equation. Firstly, we must find the gradient at the point S given by dy/dx. Using the p...
MF
Answered by Marcus F. Maths tutor
8378 Views