Express 9^(3x+)1 in the form 3^y giving y in the form of ax+b where a and b are constants.

Fistly show that: 9^3x+1=3^y

To find x we need to get the left hand side of the equation to be 3^m(3x+1) where 3^m=9.

I know that 3²=9 (but if you don't you can use m=log₃(9)=2)

This gets us: 3^2(3x+1)=3^y

Therefore: 2(3x+1)=y

Finally y=6x+2 so a=6 and b=2