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The points A and B have position vectors 2i + 6j – k and 3i + 4j + k respectively. The line l passes through both A and B. Find a vector equation for the line l.

First you need to find the vector AB. This is equal to -OA+OB. OA and OB are equal to the position vectors of A and B respectively so -OA+OB= -2i - 6j + k + 3i + 4j + k = i - 2j + 2k = AB Then we can take an...
AT
Answered by Alex T. • Maths tutor
17184 Views

Solve the equation x=4-|2x+1|

This type of equation involves a modulus, this the component enclosed in the straight lines, |2x+1|. A modulus takes the absolute value of its contents, this means that regardless of the input you always hav...
BC
Answered by Benjamin C. • Maths tutor
18790 Views

Find the derivative of the following expression: y=x^3+2x^2+6x+5.

As the expression contains 4 separate terms that are added together, we can treat this as 4 separate differentiations. The general rule for differentiation for a general term bx^n is (b n)x (n-1) . For examp...
MN
Answered by Matthew N. • Maths tutor
5321 Views

y = 6x^2 + 8x + 2. Find dy/dx

y = 6x 2 + 8x + 2 To find the first derivative of this equation, we must multiply the powers of x with the coefficient. Therefore, we do 2 times 6 (2 is the power and 6 is the coefficient) for the first term...
RD
Answered by Raj D. • Maths tutor
9479 Views

Find the area encompassed by y=(3-x)x^2 and y=x(4-x) between x=0 and x=2.

This is an integration question. The limits have been provided. Firstly find the integral for the first curve int{x(4-x)}dx int{4x-x 2 }dx 2x 2 -x 3 /3 Apply the limits x=2,0 [2(2) 2 -(2) 3 /3]-[2(0) 2 -(0) ...
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Answered by Anthony D. • Maths tutor
3956 Views