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Quantitative and qualitative testing are important aspects to consider when selecting a material or materials for a specific product. Explain what you understand by each of these terms.

Quantitative testing is objective and can often be judged numerically. For example, 'The material must weigh no more than ......' is an example of a quantitative specification point. Qualitative testing is u...
DD
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Curves C1 and C2 have equations y= ln(4x-7)+18 and y= a(x^2 +b)^1/2 respectively, where a and b are positive constants. The point P lies on both curves and has x-coordinate 2. It is given that the gradient of C1 at P is equal to the gradient of C2 at P.

y= ln(4x-7)+18 y= a(x^2 +b)^1/2 At x=2 dy/dx = dy/dx and y =y At x =2 y = ln(8-7) +18 y = ln 1 +18 y =18 At x = 2 18=a(4 +b)^1/2 18/(4+b)^1/2= a y=ln(4x-7)+18dy/dx= 4/(4x-7) At x= 2 dy/dx= 4/8-7= 4 y=a(x^2 +...
JM
Answered by Jordan M. • Maths tutor
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Calculate the value of the definite integral (x^3 + 3x + 2) with limits x=2 and x=1

a) Integrate the given expression using integration laws we have learnt to give [(x^4)/4 + (3(x^2))/2 + 2x ] and you do not need a +c constant as we have limits.b) Substitute the limits into the equation we ...
Answered by • Maths tutor
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Solve the inequality 6x - 7 + x^2 > 0

Firstly rearrange the quadratic such that the coefficient of x 2 is positive (already done in this example) and the quadratic is in the form of ax 2 +bx + c, then solve for x, like you would solve a regular ...
Answered by • Maths tutor
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Potassium Chlorate(VII) decomposes to produce Potassium Chloride and Oxygen. Using the following data calculate the enthalpy change of this decomposition: Enthalpy of formation(KClO4) = -430 kJ mol-1, Enthalpy of formation(KCl) = -440 kJ mol-1

Firstly the equation of this decomposition should be worked out to be the following KClO 4 (s) --> KCl(s) + 2O 2 (g) The enthalpy of formation has been given for both KClO 4 and KCl, so from this we know ...
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