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Find equation of line 1 in terms of x. eg y=mx+c - Using gradient and points. Equation of line 2 is just y=-3xSo -3x=mx+c of line 1Find xSub into one equation to find the y point.Done

d = kt². 45 = k x 3². 45 = k x 9 (/9). 5 = k.3+7 = 10 seconds total as we are investigating the NEXT 7 seconds. d = kt². d = 5 x 10². d = 5 x 100d = 500m in 10 ...

first begin by expanding the brackets using the CLAW method (shown using whiteboard diagram)multiply the first of each bracket together, we get x²multiply the first term of the first bracket an...

root3 (root6 + root12) (root3 * root6 ) + (root3 +root12) = root18 + root36= (root9 + root2) + 6= 3root2 +6a= 3 b = 6

v^2 = 12^2+2(-3)(18) = 36. Therefore by square rooting v = 6.To make s the subject first minus u^2 from both sides to have v^2 -u^2 = 2as then divide 2a from both sides to have (v^2-u^2)/2a = s