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Maths
GCSE

Find the values of x and y using the simultaneous equations: x+y=11, y-6=15

First solve the equation with only one unknown to find y:y-6=15Add 6 to both sides to get the value of y:y=15+6y=21Now there is only one unknown we can solve for x:x+21=11x=11-21x=-10Check the values are ...

JF
Answered by Jack F. Maths tutor
3165 Views

Simplify : 4(x+5) / x^2+2x-15

Firstly, remember to factorise!
x^2+2x-15 = (x+5)(x-3)
∴ the numerator and denominator now both share a common term "(x+5)", so they can cancel one another out, leaving the answer as :...

SP
Answered by Sohum P. Maths tutor
5268 Views

Work out: 0.7 + 3/5

Show 3/5 as a decimal: 0.6
0.7 + 0.6 = 1.3
OR
Show 0.7 as a fraction: 7/10
Find a common denominator: 3/5 = 6/107/10 + 6/10 = 13/10 or 1 and ...

EB
Answered by Edward B. Maths tutor
3977 Views

Solve the following simultaneous equations: 2x + 2y = 14; 4x - 2y = 10

By Elimination:
We can add the equations together because +2y and -2y will cancel out: 2x + 4x = 14 + 10
This gives 6x = 24, so x = 4
We can put x back int...

EB
Answered by Edward B. Maths tutor
4259 Views

A quadrilateral has a perimeter of 42cm. Three sides have equal length and the fourth side is longer by 6cm. What is the length of the fourth side?

We can call the sides of the equal lengths "x".
We can then make an equation to satisfy the relationship between the perimeter and the length of the sides as follows:
x + x + x + (x + ...

EB
Answered by Edward B. Maths tutor
2580 Views

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