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We use the form ax^2+bx+cTo factorise we need to put the equation into 2 bracketsThese 2 brackets will be in the form (x+k)(x+j) where k and j are to be foundWe need to find a combination of k and j for w...
Let's label the equations x2 + y2 = 25 (1) y - x = 1 (2). We can use substitution to solve this simultaneous equation. Let's make y the subject of the equation (2) and we get y = x...
Firstly, you need to get the equation to equal zero, so that you can use the quadratic formula to solve. Therefore you subtract 7 from both sides, meaning the equation becomes: 3x^2+7x-20=0. Recall the qu...
(6x-2)/4 - (3x+3)/3 = (1-x)/3multiply both sides of the equation by 12=lowest common multiple of 4 and 33(6x-2) - 4(3x+3) = 4(1-x)expand brackets18x - 6 -12x - 12 = 4 - 4xsimplifyELAnswered by Eleanor L. • Maths tutor2823 Views
So far in your learning it is likely that you have been learnt that if you can't factorise a quadratic equation then you can not solve for x. The quadratic formula is overcomes this restriction, allowing ...
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