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2^6 = 64 (2x2x2x2x2x2)6^2= 36 (6x6) 64+36= 100Square root of 100= 10 (10x10=100)
a^2 + b^2 = c^2c^2 = 8^2 + 6^2c^2 = 64 + 36c^2 = 100c=10
Since there is a common factor of 3 on the the left hand side of the equation, you can take that out as a factor:3(x^2 + 2x +1) = 0Then you you can divide both sides by 3:x^2 + 2x + 1 = ...
To answer this question it is best to remember SOH CAH TOA.SOH: sin(angle)=opposite (length of side opposite the angle)/hypotenuse (length).CAH: cos(angle)=adjacent (length of side next to the angle)/hypo...
The first think you can do is look to see if all of your terms can be divided by a common factor. In this case it is 3, leaving you with 3(x^2 - 3x - 10). This can be factorised further to produce somethi...
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