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Equation of this type should be seen as x²-SX+P=0, where S is the sum of the solutions, while P is their product. We have too find 2 numbers whose sum is S and product is P. In this example, we...

1. Identify a common denominator4(x +1)/12 + 3(2x + 5)/12 (= 2)2. Expand both brackets(4x + 4)/12 + (6x +15)/12 = 23. Multiply out the denominator4x + 4 + 6...

Divide the term in x by 2 and then put it in the bracket which will be squared. The last term from that expansion needs to be adjusted for.

(3x^2+14x-5)(4x-3)= 12x^3-9x^2+56x^2-42x-20x+15=12x^3+47x^2-62x+15

Area of a Circle = πradius² Area of Garden = π30*30 = 2827.43 m²Boxes needed = 2827.43/28 = 101