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By looking at the equation you see it is made up of three components. The way to factorise it is to multiply the integer or constant at the end by the coefficient of the x 2 term, the number be...
9(x+3)-2(3x-4)9x+27-6x+83x+35
When dealing with questions to do with expanding brackets, you must multiply every term in one bracket with all the others in the second bracket. So for this question, we can see we have 4 termsAAAnswered by Ameer A. • Maths tutor5410 Views
With simultaneous equations there is more than one unknown. First we’ll get one unknown on its own so we rearrange the bottom equation to get x on its own. By adding y to each side of the equation this le...
To begin this question you need to bring all of the terms to one side, so the equation equals 0. It is easiest to do this by subtracting 1 from each side.x^2-3x-3-1=1-1x^2-3x-4=0Now we need to factorise t...
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