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Step 1, find the gradient of line A: gradient = change in y/change in x = (y1 - y2) / (x1 - x2) = 9-3/4-2 = 6/2 = 3Step 2, find the gradient of line B: as the two lines are perpendicular, the gradient of ...
3x + 2 = 11 . 3x = 9 . x=3 .
The aim of this question is to end up with 'x' standing by itself on one side of the equation. The key principle to achieve this is to understand that whatever you do to one side of the equation, you have...
Let’s call (f(x)=2x+c) equation 1, (g(x) = cx+5) equation 2 and (fg(x)= 6x+d) equation 3.Start by finding fg(x) in terms of c by substituting (equation 2) into (equation 1) to get (fg(x)= 2(cx +5) +...
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