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Maths
GCSE

How do you find the gradient of a linear line just by looking at the graph?

When finding the gradient of a line we need to first locate any two points, on the line, where we know the x-coordinates and we know the y-coordinates. Now, with these two coordinates we need to find two ...

JS
Answered by Jozef S. Maths tutor
2558 Views

Find f^-1(x) for the following equation: f(x) = (12+x)/3

f-1(x) is equivalent to the inverse of the function f(x). To solve the inverse of a function, a series of steps must be followed:
1) Write out the equation x = f(y)
T...

BW
Answered by Bethany W. Maths tutor
3034 Views

Solve algebraically the simulations equations: x^2+y^2=25 and y-3x=13

x2+y2=25; y-3x=13; x2+(13+3x)2=25; x2+9x2+78x+169=25; 10x2+78x+144=0; 5x2+39x+72=0; (5x+24)(x+3)=0; x=-24/5 and y=-7...

NC
Answered by Nadia C. Maths tutor
2815 Views

The equation of the line L1 is: y = 5x-4. The equation for line L2 is 2y-10x+16 = 0. Show that these two lines are parallel.

L1: y=5x-4L2: 2y-10x+16=0. Rearranged: 2y=10x-16, y=5x-8 The coefficient of x is the same in both equations when expressed in standard format (5), therefore the lines are parallel.

AW
Answered by Alfie W. Maths tutor
4730 Views

Solve x^2+4x-5=0

Two approaches.1.Note that the equation is a quadratic equation, and can thus be solved per the quadratic formula, in which the solutions are given to be (-b+-sqrt(b^2-4ac))/2a.Plugging in the values from...

SH
Answered by Samuel H. Maths tutor
3827 Views

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