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To do this we will assume sqrt(2) is rational, a fraction, which means: 21/2 = m/n; m,n belong to integers. Also, m/n is an irreductible fractionJCAnswered by Joao C. • Maths tutor3173 Views
Firstly we will start by expanding the brackets. We will do 2a + 23 for the first bracket, then we will do 5a + 5(-1) for the second bracket which will give us 2a + 6 + 5a - 5. We will ...
In order to solve a quadratic equation by factorisation you must first find the two numbers which add up to - 8 and multiply to get 15. We can do this by trial and error - first listing all of the pairs o...
The at first can seem very challenging and you won't be able to tackle this question quickly using simple factorisation, which you can often do for many questions. It is best in this case then to use the ...
This question can be answered by the elimination method, substitution method or graphically. I find the elimination method easiest, especially when you can see that the coefficient of a variable (in this ...
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