Top answers

Maths
GCSE

How do I solve a quadratic equation?

All quadratic equations can be written in the form ax2 + bx + c = 0, where a, b and c are constants. Firstly, check whether you can easily factorise the equation into the form (x + p)(x + q) = ...

MS
Answered by Matthew S. Maths tutor
4134 Views

By completing the square, find any turning points and intersects with the x and y axes of the following curve. f(x) = 2x^2 - 12x +7

f(x) = 2x2 - 12x +7

  • First take out a factor of 2 so that we have the coefficient of x2 as 1.        f(x) = 2[x2 - 6x +7/2]

  • Next, complet...

FI
Answered by Freddie I. Maths tutor
22991 Views

Solve the inequality 5x + 3 ≤ 3x − 6

The first step that we need to take is to take all the 'x' terms to one side of the inequality. In this case, we can subtract '3x' from both sides to obtain 2x+3 ≤ -6. Then we want to take all the non- x ...

RU
Answered by Ritvik U. Maths tutor
5709 Views

(6/x-2)-(2/x+3)=1

a) This question tests you on using fractions, brackets and quadratic equations.  We should start by trying to make it into a form we know how to deal with. This will be by the balance method. If we multi...

BV
Answered by Benjamin V. Maths tutor
2640 Views

Make y the subject of the equation: t=(y+2)/(4-y)

Multiply by 4-y   => t(4-y)=y+2 Expand the brackets  => 4t-ty=y+2 Get all the y's on the same side => 4t-2=ty+y Factor out the y  => 4t-2=(t+1)y Divide by t+1  => (4t-2)/(t+1)=y

CM
Answered by Christopher M. Maths tutor
3201 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning