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Maths
GCSE

Solve for x, y, and z: 5x - 2y = 19 , 3x + 3z = 21 , y + z = 2

Like when there are two unknowns, the best way to solve this kind of problem is to rearrange and substitute, but because there are three unknowns, it's a bit more fiddly. To solve this you want to pick an...

DT
Answered by Dan T. Maths tutor
7416 Views

A gym has 275 members. 40% are bronze members. 28% are silver members. The rest are gold members. Work out the number of gold members.

Firstly, we can calculate the total percentage of gold members = Total - bronze - silver

Therefore, %gold = 100% - 40% - 28% = 32%

So we know that 32% of 275 members are gol...

SS
Answered by Sarah S. Maths tutor
9680 Views

How to calculate sin, cos and tan

SOH CAH TOA (imagining each as a triangle)

S = sin

C = cos

T = tan

O = opposite

H = hypotenuse

A = adjacent

PH
Answered by Phoebe H. Maths tutor
3022 Views

Solve the simultaneous equations: 5x + 3y = 41 and 2x + 3y = 20 Do not use trial and error.

  1. 5x + 3y = 41   2) 2x + 3y = 20 Subtract equation 2) from equation 1) to cancel the y's (3y-3y = 0) .  Next we subtract  the x's (5x - 2x = 3x) and then finally we have 41 - 20 = 21. We now have that...
DT
Answered by David T. Maths tutor
19019 Views

Solve the equation "x^2 + 3x - 4 = 0".

Recognise that quadratic can be factorised:

(x+4)(x-1)=0

This gives the solutions x=-4 and x=1 by inspection.

ZK
Answered by Zak K. Maths tutor
3300 Views

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