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0= (x + 4)(x + 1)

x= - 4

x= - 1

(4x-5)^2-5x(3x-8)

(16x^2-40x+25)-(15x^2-40x)

16x^2-15x^2-40x+40x+25

x^2+25

if x = positive, x^2 will be positive.

if x = negative, x^2 will be positive.

x^2 is po...

x=0.81

A simple implementation of Pythagoras' Theorem a²+b²=h², and as in the question c is the hypotenuse, a²+b²=c². (Side Note - in exams, the ...

Solve: 2x - y = 4  and x + 2y = 7

There are two methods to solve this, you can either calculate one of the variables from either equations and then substitute to the second one or try to multiply o...