Top answers

Maths
GCSE

Explain the use of the quadratic formula to solve quadratic equations.

To explain this to a student, I would start by explaining the general formula for a quadratic equation, (ax^2 + bx + c = 0). Then I would show using an example, how the a,b and c can be substituted with n...

TN
Answered by Tom N. Maths tutor
2756 Views

How would you work out the length of an hypotenuse, if the length of the opposite side is 3 cm and the length of the opposite side is 4 cm?

You would use Pythagoras theorem, which states, a^2 + b^2 = c^2. Where a is the opposite side to the angle, b is the side adjacent to the angle and c is the hypotenuse.

So if a = 3 cm, and b = 4 c...

OA
Answered by Othniel A. Maths tutor
3733 Views

Solve the simultaneous equations: 2x+2y=12 x-y=8 You must show your working

The first thing we want to do is change the first equation so it's either all x's or all y's, we don't want a mixture. Now looking at the bottom equation, we can rearrange it by adding y to both sides. Th...

KA
Answered by Kasim A. Maths tutor
5075 Views

How do I rearrange this equation for x? y=(x+2)/(3x-1) +2

First of all we must consider the fraction. To eliminate this we multiply both sides through by 3x-1. We then end up with y(3x-1)=(x+2)+2(3x-1). The next step is to expand out the brackets and collate ter...

CM
Answered by Charlie M. Maths tutor
4262 Views

Show (4+5/7) - (2+1/3) as a single mixed fraction.

Mixed number -> top heavy fraction: 4 + 5/7 = ((47)+5)/7 = (28+5)/7 = 33/7 2+ 1/3 = ((23)+1)/3 = (6+1)/3 = 7/3 Common denominator by multiplying by each others: 33/7 = (333)/(73) = 99...

ER
Answered by Ethan R. Maths tutor
3498 Views

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