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solve 2x^2+4x-7=0

Notice that this is a quadratic. First you should try factorisation, then if unsuccessful try completing the square (or the quadratic formula). In this example, factorisation is not possible (I can this f...

Answered by Katie W. • Maths tutor

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Solve the simultaneous equations: y=x/2 + 2 and 2y+3x=12

Label the equations (1): y=x/2 + 2 and (2): 2y+3x=12. Firstly, multiply equation (1)by 2, this will give you (1a): 2y=x+4, then, substitute (1a) into (2). This gives you (x+4)+3x=12. Therefore, 4x+4=12. 4...

Answered by Joseph B. • Maths tutor

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Solve the equation x^2-9x+20=0

First, we need to factorise the equation on the left hand side, this can be done by finding two numbers that add together to make the 'b' coefficient (-9) and multiply to make the 'c' coefficient (20).

Answered by Joseph B. • Maths tutor

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Simplify 3x^(2)+13x-30/x^(2)-32

First of all spot that the bottom of the fraction is a result of the difference of two squares and can be rearranged to (x+6)(x-6), making the fraction equal to 3x^(2)+13x-30/(x+6)(x-6). Use this knowledg...

Answered by Nicolaas P. • Maths tutor

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Solve (4-2x)/(x+1)=x

To solve this equation, we need to collect all of the x^2 terms and the x terms together. To do this we should start by getting rid of the fraction on the left-hand side by multiplying both sides by the d...

Answered by Emily K. • Maths tutor

9146 Views