Search our library of Maths GCSE questions

Top answers

Maths

GCSE

How do you solve simultaneous equations?

The easiest way to solve simultaneous equations is by elimination. This is the idea of cancelling out one of your variables, the X or Y so that you can solve the remaining variable and then substitute thi...

Answered by Ben H. • Maths tutor

3347 Views

Expand (x+4)(x+3).

To answer this you multiply everything in the left bracket by everything in the right bracket, so rewrite the equation as x(x+3)+4(x+3). Then you can expand each more easily:

x(x+3) = x

Answered by Elliot D. • Maths tutor

28761 Views

Simplify: 2x +6y +2y - x

collect x terms together i.e.) 2x - X = 1x and then collect y terms together i.e) 6y + 2y = 8y add your two answers together to get: x + 8y

Answer x +8y

Answered by Sophie M. • Maths tutor

6167 Views

If a and b are the roots of the quadric polynomial 2x^2+6x+7 what are a+b and ab?

The phrase "a and b are roots of 2x^2+6x+7" is just a way of saying that x=a and x=b solve the equation 2x^2+6x+7=0. Check out that by diving by 2 on both sides of this equation we get that that...

Answered by Guillermo C. • Maths tutor

3188 Views

A bag contains beads, 60% of which are green. A student claims that the probability of getting two green beads if the beads aren't replaced is 1/3 as 6/10 * 5/9 is 1/3. Is the student right?

They have multiplied the fractions correctly but they are still incorrect. The student has assumed that a bag with 60% green beads contains 10 beads. If the bag had 100 beads and 60 were green, 60% of the...

Answered by Adithya K. • Maths tutor

3221 Views