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Add the 2 eqns together to eliminate the y's to give: 4x=4. Divide by 4 to give x=1Now substitute x=1 into the first eqn: 3+2y=7. Subtract 3 from both sides -> 2y=4. Divide by 2 to give y=2.Now, check ...

-Firstly we should check if the equation has the variables separated (x on one side and y on the other side of the equal sign), which they apear to are, therefore we can proceed to the next step. As it is...

6x³ + 8x² -15x = 0x(6x² + 8x - 15) = 0x=06x² + 8x - 15 = 0Quadratic formula ( can demonstrate in interview)x = 0 or x = 1.049 or x = -2.38

first of all we have to recognise the general form of the equation, similar to the equation of a line but we just have to add one more term due to the fact that it is a second degree equation: y=ax^2<...

using pythagorus ( c^2 = b^2 + a^2) and plugging in 3 and 4 as a and b we get c^2 = 3^2 + 4^2 = 9 + 16 = 25. Taking the positive square root as sides can't be negative we get c = 5