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y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(...

For this question it is key to remember the indices laws. The ones you need to recall for this question are: x^a / x^b = x^{a - b}, and (x^a)^b = x^{a * ...}

= We start by halfing the 10 and putting x + 5 in a bracket = (x + 5)^2 = Opening these brackets give us x^2 + 10x + 25 = To make the 25 the same as - 3 we have to minus 28 = Therefore the answer is = (x ...

dy/dx = 4x - 12
x-coordinate= 5 so sub in
20-12 = 8

First of all there are 3 different methods of working out simultaneous equations: Elimination, Substitution and Graphical. Today I will show the substitution method.
If x + y = 4 then rearranging the...