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We have 2 fractions we want to get rid off to make it easier, so what we do is multiply both sides by the things we want to get rid off.In this case we multiply both sides by (2x-3)(x+1)This gives us x(x+...

2x² - 2y = 282y - 4 = 12x
y - 2 = 6xy = 6x + 2
Substitute y = 6x + 2
2x² - 2(6x + 2) = 282x² - 12x - 4 = 282(x² - 6x - 2) = 28x² - 6x ...

Pythagorus' theorem a^2 + b^2 = c^2
4^2 + 5^2 = c^216+25 = c^241 = c^2Root 41 or 6.403 = c

To work out the mean, we first add up all of the scores so 4+4+7+3+9+10+5+8= 50. We then divide by the number of student who took the test, or the number of scores given, which is 8. Divide 50 by 8 to giv...

Use factorisation to solve this. You must find a pair of numbers that add to make 6 and multiply to make 5. In this question, 5 and 1 add to make 6 and they also multiply to make 5. So the factorised equa...