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Maths
GCSE

Solve this equation: x²-x-6=0

This equation can be solved by factorisation. Start off with brackets : (x )(x ) =0. We need two numbers that multiply to give 6 and add/subtract to give 1. Start off with 1 and 6. They multiply to give 6...

ED
Answered by Eadaoin D. Maths tutor
2983 Views

The perimeter of a right-angled triangle is 60cm. The lengths of its sides are in the ratio 3:4:5. Work out the area of the triangle.

Draw out a diagram of a right angled triangle. As the lengths of the sides of the triangle are in the ratio 3:4:5, start off by saying each side is 3cm (a), 4cm (b) and 5cm (c) respectively, with 5cm bein...

ED
Answered by Eadaoin D. Maths tutor
5042 Views

Solve x^2-5x+6=0

We can factorise into (x-3)(x-2)=0 to get x=3 and x=2 as solutions for this equation.

TM
Answered by Thomas M. Maths tutor
2590 Views

Simplify the following fraction - Numerator = 2(8-k) + 4(k-1) Denominator = k^2 - 36

The first task is to multiply out the brackets in the numerator. By doing this, we find that the numerator is equivalent to "12 + 2k". We should now simplify the denominator. We can convert it i...

ML
Answered by Matteo L. Maths tutor
3196 Views

a) Find the area of a semi circle with diameter 12cm. b) The area of a semi-circle is 60cm^2. Find the radius of the sem-circle.

a) radius = 12/2 = 6cm. Area of a circle = pi x r^2 = 36pi. Area of semi-circle = 36pi / 2 = 18pi cm^2b) Area of full circle = 120. pi x r^2 = 120. r^2 = 120/pi. r = sqr root (120/pi)= 6.18cm

AG
Answered by Ahmed G. Maths tutor
4961 Views

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