Search our library of Maths GCSE questions

Top answers

Maths

GCSE

Solve 7x + 6 > 1 + 2x

7x + 6 > 1 + 2xFirst, we collect the like terms so we move all the x's to one side and all the integers to the other:5x > -5Then we divide by 5 on each side to find what just x will be.Therefore, x ...

Answered by Juliet Z. • Maths tutor

2557 Views

Solve the simultaneous equation, 3x + y = 8 and x + 3y = 12, to find a value for x and y.

Re arrange one of the equation to get a single variant answer. So, x = 12 - 3y. Substitute this into the other equation, so 3 (12-3y) + y = 8. Expand this equation to form 36 - 9y + y = 8. Collect the y t...

Answered by Grace R. • Maths tutor

5763 Views

Show that (x + 4)(x + 5)(x + 6) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.

=(x+4)(x²+6x+5x+30)=(x+4)(x²+11x+30)=x³+11x²+30x+4x²+44x+120=x³+15x²+74x+120

Answered by Jiawen Z. • Maths tutor

2534 Views

The Diagram shows the Triangle PQR. PQ = x cm. PR = 2x cm. Angle QP^R = 30 degrees. The area of the triangle PQR = A cm^2. Show that x = (Squared Root){2A

Area of a Triangle Formula is
A = 1/2 abSINc
Label the sides of the triangle PR = 2x = a PQ = x = b
1/2 (x) 2x (x) x (x) SINc = A = x²SINc
Rearrange the equation to give...

Answered by Tutor305386 D. • Maths tutor

10012 Views

Solve the simultaneous equations 'x-2y=3' and 'x^2+2y^2=27'

Equation 1: x-2y=3Equation 2: x²+2y²=27The easiest way to do this is to put one of these equations into the other, by rearranging for either x or y. Because there are no squares to d...

Answered by Tahmid K. • Maths tutor

6589 Views