Search over 10,000 free study notes

completing the square (x+5)² -25 -3 =0 (x+5)² -28 = 0 (x+5)² = 28 x= ±2√7 -5

The easiest way to approach this is by trying to find two numbers which add up to the x coefficient (the number attached before the x) and multiply to the constant (the number on its own). For example...x...

It's easier if we first visualise the function on a graph, then we can see in which regions it is negative. From there we can see which integer values lie in this region. A positive quadratic function has...

You want to make the equations equal one another. If both equal y it can be written like this: x²+2x-2=4x+6Then simplify by putting the terms on one side and equaling 0: x²-2x-8Now p...

y = k √x20 = k √49 20/7 = ktherefore y = 20/7 √x