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x+10=0x= -10x-16=0x= 16

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60.

a = 4b = 60

We must use the substitution method for this question because the first equation is a quadratic. Take the more simple equation (the second one), and use that to substitute the value for y in to the first ...

To solve these simultaneous equations there are two different methods that could be used. The first one to try in this case is to start with rearranging one of the equations to get a value of y by itself....

equation 1: 2y + x = 8equation 2: 4 + 4y = 8xSolve by substitution;simplify equation 12y + x = 8 x = 8 - 2ysubstitute into equation 2 4 + 4y = 8(8 - 2y)4 + 4...