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Maths
GCSE

3 teas and 2 coffees have a total cost of £7.80. 5 teas and 4 coffees have a total cost of £14.20. Work out the cost of one tea and the cost of one coffee.

Firstly we need to set up a simultaneous equation. 3t +2c =7.80 and 5t +4t = 14.20 Rearrange the first equation to find c on its own. 2c = 7.80 - 3t, c= (7.80 - 3t) / 2Then put the new value of c into the...

LB
Answered by Louise B. Maths tutor
4102 Views

Solve the simultaneous equations y = x + 3 and y = x^2 + 3x

Step 1: Recognise the quadratic term, this cannot be solved through elimination. Therefore we must need to use substitution. Substitute y = x + 3 into the quadratic. Gives x + 3 = x2 + 3xStep 2...

SN
Answered by Sam N. Maths tutor
6301 Views

n is an integer such that 3n + 2 ≤ 14, and 6n/(n^2 + 5) >1. Find all possible values of n.

Step 1: Simplify 3n + 2 ≤ 14 3n ≤ 12 n ≤ 4 and 6n > n^2 + 5 0 > n^2 -6...

CM
Answered by Catriona M. Maths tutor
10207 Views

Solve (x+10)(x-16)=0

x+10=0x= -10x-16=0x= 16

ST
Answered by Sophie T. Maths tutor
2706 Views

(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60.

a = 4b = 60

AE
Answered by Aeron E. Maths tutor
7623 Views

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