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Step 1: Factorise the equation either directly or by using the quadratic formulae {[-b(+/-)sqrt(b^2-4ac)]/2a}. This equation can be factorised directly since 3*3=9 (for the last term on the RHS) and 3+3=6...

Example solve the following, equation 1: x²+2y=9 equation 2: y=x+3In this example we have to use substitution, therefore we sub in equation 2 into 1 to get the following x²+2(x+3)=9 ...

2^6 = 64 (2x2x2x2x2x2)6^2= 36 (6x6)
64+36= 100
Square root of 100= 10 (10x10=100)

a^2 + b^2 = c^2c^2 = 8^2 + 6^2c^2 = 64 + 36c^2 = 100c=10

Since there is a common factor of 3 on the the left hand side of the equation, you can take that out as a factor:
3(x^2 + 2x +1) = 0
Then you you can divide both sides by 3:
x^2 + 2x + 1 = ...