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Since there is a common factor of 3 on the the left hand side of the equation, you can take that out as a factor:
3(x^2 + 2x +1) = 0
Then you you can divide both sides by 3:
x^2 + 2x + 1 = ...

To answer this question it is best to remember SOH CAH TOA.SOH: sin(angle)=opposite (length of side opposite the angle)/hypotenuse (length).CAH: cos(angle)=adjacent (length of side next to the angle)/hypo...

The first think you can do is look to see if all of your terms can be divided by a common factor. In this case it is 3, leaving you with 3(x^2 - 3x - 10). This can be factorised further to produce somethi...

You should start off by separating the brackets as the squared only applies to one of them. We'll deal with that one first. Write the (2x + 3y)^2 as two separate brackets of (2x+3y). Then multiply the fir...

Look for factors of 15 then when adding together equal -8. A solution to this is -5 and -3 as -5 x -3=15 and (-5)+(-3)=-8 . Therefore the factors of the quadratic are (x-5) and (x-3). Make (x-5)(x-3)=0 so...