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Maths
GCSE

Solve the following simultaneous equations: 6a + b = 16; 5a - 2b = 19

There are 2 methods in solving this set of equations, in order to find the 2 unknowns: (a) and (b). Method 1: Firstly rearrange equation 1 to make (b) the subject: b = 16 - 6a. This can then be substitute...

DC
Answered by Doroti C. Maths tutor
3471 Views

Solve the simultaneous equations. (1) 2x + y = 18 (2)x − y = 6

In these simultaneous equations, there are two unknowns. The first is x, the second is y. The aim of a question like this is to find what x and y are equal too. A method to doing this is to rewrite one eq...

SW
Answered by Samantha W. Maths tutor
4559 Views

If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle)(x-4)(x-5)=12x2-9x+20=12x2

SM
Answered by Simon M. Maths tutor
3294 Views

Factorise x^2+6x+8

Firstly, as it's highest term is x2, it must only have two factor brackets, so the answer has to look like (x + a) * (x + b).Then, to make 6x, we need the a and b term to be either 5 and 1, 4 a...

TM
Answered by Tom M. Maths tutor
14147 Views

Show that the two lines are parallel: L1: 4y = 24x +12, L2: 2y + 13 = 12x

Two lines are parallel when they have the same gradient.
When the equation is written in the form: y = mx + c, m is the gradient.
We need to arrange our equations in the form y = mx + c as this...

DT
Answered by Dominique T. Maths tutor
19161 Views

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