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I would tell them to start multiplying out the first brackets (x+2)(x+3)! I would do this by timesing x by everything in the second bracket and then 2 by everything in the second brakcet! Giving the answe...

We can solve simultaneous equations one of two ways. We can either substitute one equation into the other or we can eliminate one of the unknowns only leaving us one to deal with. I will explain both meth...

1.Simplify the two equations: 4x+y=17and 2x+y=9. 2. Rearrange one of the equations to make y=: y=9-2x. 3.Substitute into other equation:4x+9-2x=17. 4. Simplify:2x=8 x=4. 5.Substitute back into either of t...

Quadratic formula: where ax^2+bx+c =0, x = (-b±√(b^2-4ac))/2a.Rearrange the formula in the question to get 3x^2+4x-20 = 0.From the quadratic in the question we can see that a = 3, b = 4, c = -20.Therefore...

_{The correct answer is: 4x+3. The first part of the equation is differentiated by multiplying the power by the constant in front (2*2). The power is then reduced by one to x^1 (which is just x). This ...}