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I would start off by asking them if they know the Pythagoras theorem. If they don't, I would refresh their memory and explain that its a2+b2=c2 where...
Start by multiplying equation (2) by 4 so both equations contain 4 lots of x: 4x - 12y = 20 Then take away equation 1 from equation 2 to eliminate x -13y = 13 divide by 13 and then reverse the negative si...
expand the brackets to get x2-2x+3x-6=4x+22 bring all the terms to one side x2-2x+3x-6-4x-22=0 (remember:if you do something to one side, do the same thing to the other! e.g. -4x on ...
To solve the inequality, it must first be factorised. This could be done by the ‘complete the square’ method. However in this example it is more efficient to find a pair of numbers that multiply to give t...
Whenever you have a question asking you to solve an algebraic equation with only one unknown (x) you must put all 'x' terms on one side of the equation and all non-'x' terms on the other: 1. Take 2x away ...
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