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Maths
GCSE

Solve the simultaneous equations: 2x - y = 1, 3x + y = 14

Make y the subject of equation 1:y = 2x - 1Substitute this value of y into equation 2:3x + (2x - 1) = 14Simplify:5x - 1 = 14Solve for x:x = 3Substitute this value of x into original equation:2(3) - y = 1S...

SB
Answered by Stephen B. Maths tutor
4107 Views

solve simultaneous equations: 2x² + 3y² = 14 , x = 2y-3

x=1y=2
x= -29/11y=2/11

AG
Answered by alasdair g. Maths tutor
6814 Views

Make s the subject of the formula

v2 = u2 + 2as. The question is asking us to make s the subject of the formula and so we must find the equation equal to s. The golden rule of the rearranging topic is whatever you do...

SH
Answered by Samuel H. Maths tutor
6037 Views

Find the roots of the equation: x^2-2x-3=0

The point at which the explanation of the solution is started, will depend on the level of understanding of the student and previous knowledge on the subjectA root is a numerical value that repre...

AP
Answered by Andreas P. Maths tutor
5164 Views

Simplyfy, ((x-2)(x^2+5x+6)-(2x^2+10x+12))/(x^2+x-2)

The key to this is to not expand everything out and try work it out through that process. The easiest way is to notice that (x^2+5x+6) = (x+2), (2x^2+10x+12)=2(x+3)(x+2) and (x^2+x-2)= (x+2)(x-1).From thi...

TL
Answered by Thomas L. Maths tutor
2807 Views

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