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5x - 2 > 3x + 11
5x - 3x > 11 + 2 
2x > 13
x > 13/2 
x > 6.5

First list what the question gives you. 

p=36    r=3      t=-2

Sub in the values that you know into the equation.

Q= 36/ 3(4--2)

Q= 36/18

Q=2

6x^2 + 5x +7 =y

dy/dx = 12x + 5 

To solve for a point of inflection:

dy/dx = 12x + 5 = 0

x=-5/12

y=143/24

As the tangent meets the circle at P, when x =1, we can assume that the y value will be the same for this value of x. therefore we substitute x=1 into the equation of the cirlce. Rearranging the equation ...

i) (5 x 4) -12 = 8 ii)  5(x + 1) - 12 5x + 5 -12 5x - 7