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Maths
GCSE

Solve the simultaneous equations: 4x+y=25 and x-3y=16

Lets first give the equations names.

4x+y=25 (A)

x-3y=16 (B)

We want to get the equations so that they have either the same number of x's or same number of y's. So let's multiply equa...

MD
Answered by Michael D. Maths tutor
8726 Views

The area of a rectangle is 8cm^2. It has a length of (3x+1)cm and a width of (2x+5)cm. Work out the value of x.

We know that the equation of the area of a rectangle is width times by length. Therefore:

8=(3x+1)(2x+5)

If we multiply out the brackets we get:

8=(6x2+2x+15x+5), thus, 8=6...

OC
Answered by Oliver C. Maths tutor
11795 Views

Finding the length of the side opposite a known angle while having the hypotenuse length known

Sin x is equal to the length of the opposite side divided by the length of the hypotenuse. So, the length of the opposite side is Sin x multiplied by the length of the hypotenuse

AA
Answered by Amer A. Maths tutor
3604 Views

You area told that y is proportional to x2 and that when y = 75, x = 5. a) Find a formula for y in terms of x. b) Find the value of y when x = 3. c) Find the value of x when y = 1200.

a) when y=75 x=5 and y is proportional to x^2, so the answer is y=___x^2
if x=5, then x^2 = 25, and 75/25=3, so the answer is y=3x^2

b) if x=3, x^2=9, if you multiply this by 3, you get the a...

MB
Answered by Millie B. Maths tutor
3138 Views

Solve the following simultaneous equations: x^2-y^2=9, x - y = 1

We first notice we have a linear and non linear equation. The simplest method to solve is to substitute the linear equation into the non linear equation and then solve for one of the unknowns. Then substi...

SH
Answered by Shantu H. Maths tutor
7675 Views

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