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6a + b = 16 (1)

5a - 2b = 19 (2)

(1) x 2: 12a + 2b =32

(1) + (2): 12a + 2b + 5a - 2b = 32 + 19 = 51

17a = 51

a = 51 / 17 = 3

Substitue a = 3 back into (1): (6 x 3...

0= (x + 4)(x + 1)

x= - 4

x= - 1

(4x-5)^2-5x(3x-8)

(16x^2-40x+25)-(15x^2-40x)

16x^2-15x^2-40x+40x+25

x^2+25

if x = positive, x^2 will be positive.

if x = negative, x^2 will be positive.

x^2 is po...

x=0.81

A simple implementation of Pythagoras' Theorem a²+b²=h², and as in the question c is the hypotenuse, a²+b²=c². (Side Note - in exams, the ...