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Maths
GCSE

Solve for simultaneous equations x +5y =9 and 3x + 2y =5.

Here we have 2 unknown variables, x and y. First number the two equations, so x + 5y = 9 is (1), while 3x + 2y = 5 (2).

Rearrange both equations so that they become (1) x = 9-5y and (2) x= (5-2y)/3...

AL
Answered by Abigail L. Maths tutor
7451 Views

Washing powder is sold in two sizes: Bag 1 is 600 grams for £3.30. Bag 2 is 1500 grams and usually costs £9.60 but currently has 15% off. Which is better value?

To determine which is better value, we need to determine the price per gram of each washing powder.
Bag 1:
For the 600g bag, this is done by dividing the price by the number of ...

JL
Answered by Joe L. Maths tutor
6326 Views

At what points does the line y = x +1 intersect the circle x^2 + y^2 + 18x + 20y + 81 = 0.

The method we shall use is substitution. We shall replace y each term by 'x + 1' so we are able to obtain an equation in one variable. x^2 + (x+1)^2 + 18x + 20(x+1) + 81 = 0. We now expand the brackets. x...

HR
Answered by Harry R. Maths tutor
5150 Views

(2x + 3)/(x-4) - (2x - 8)/(2x + 1) = 1

Multiply through by both denominators, giving us the equation (2x + 3)(2x + 1) - (2x - 8)(x - 4) = (x-4)(2x +1). If we expand the brackets, we arrive at 4x^2 + 8x + 3 - (2x^2 -16x + 32) = 2x^2 -7x -4. If ...

HR
Answered by Harry R. Maths tutor
3911 Views

Solve the simultaneous equations: 3a + 2b = 17 and 4a - b = 30

Here we have a pair of simultaneous equations with two unknowns. There are two methods of going about this question: substitution or elimination. Today, we shall be focusing on the latter. We need a pair...

YR
Answered by Yashna R. Maths tutor
12371 Views

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