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Draw a graph of x = (y+4)/4.

Note: There are multiple ways to do this, so find a way that works for you!Step 1: Get rid of the fraction.Step 2: Rearrange the new formula into y = mx + c.Step 3: Find the y-intercept and the x-intercept.S...
TN
Answered by Tarin N. Maths tutor
3438 Views

How do you solve simultaneous equation where one of them involves powers?

Example: y - 3x = 2 , x 2 + y 2 = 4 y= 3x + 2 x 2 + (3x+2) 2 = 4 10x 2 + 12x + 4 = 4 10x 2 +12x=0 x(10x+12)=0 x=0 or x=-1.2 y=3 0 + 2 = 2 (0,2) is a solution y = 3 -1.2 + 2=-1.6 (-1.2,-1.6) is a solution
LF
Answered by Luke F. Maths tutor
3196 Views

Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.

y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(x+5...
TM
Answered by Theo M. Maths tutor
3979 Views

Simplify the following expression: ( (x^5) / (x^2) ) ^ 4

For this question it is key to remember the indices laws. The ones you need to recall for this question are: x a / x b = x a - b , and (x a ) b = x a * b . Using these laws, we can simplify the expression in...
SJ
Answered by Shafaan J. Maths tutor
3646 Views

Express x^2 + 10x – 3 in the form (x + p)^2 + q

= We start by halfing the 10 and putting x + 5 in a bracket = (x + 5)^2 = Opening these brackets give us x^2 + 10x + 25 = To make the 25 the same as - 3 we have to minus 28 = Therefore the answer is = (x + 5...
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Answered by Haasan P. Maths tutor
7643 Views