Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.
y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(x+5) = 0Solve for x: x=2 or x=-5when x=2: Y=8,when x=-5: Y=-5Check Values confirm: They DO ! ! WOop!
TM
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