How do you solve simultaneous equation where one of them involves powers?

Example: y - 3x = 2 , x2 + y2 = 4 y= 3x + 2 x2 + (3x+2)2 = 4 10x2+ 12x + 4 = 4 10x2+12x=0 x(10x+12)=0 x=0 or x=-1.2 y=30 + 2 = 2 (0,2) is a solution y = 3-1.2 + 2=-1.6 (-1.2,-1.6) is a solution

LF
Answered by Luke F. Maths tutor

2403 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How can I know whether to multiply or add probabilities?


What are the two roots of the equation (4x-8)(x-3) = 0?


Find the values of X and Y from the simultaneous equations: 1) 2x + 5y = 33 2) x + 3y = 19


Why is MC=MR at the profit maximizing level of output?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences