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Find the roots of the following curve: y = 6x^2 - 4x.

The two terms in the quadratic equation share the factors 2 and x , so these can be brought outside the bracket as shown: y = 2x(3x-2). In order to solve for the roots (where the curve intercepts the x-axis)...
SK
Answered by Sam K. • Maths tutor
3238 Views

Complete the square of X^2 + 4X - 12

X^2 + 4X - 12X^2 + yX + z(x + a)^2 + ba = y/2a = 4/2 = 2b = z - a^2b = -12 -2^2 = -16Therefore: x^2 + 4x - 12 = (x+2)^2 - 16
AR
Answered by Anastasia R. • Maths tutor
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Work out the value of (16/81)^3/4

Treat each component separately and break it down...Note that when a number has a power that is a fraction, the numerator acts as a power and the denominator acts as a root(16)^1/4 = 2. Okay, brilliant!So wh...
MT
Answered by Maisie T. • Maths tutor
7051 Views

Make s the subject of: v^2= u^2+2as

The aim of this question is to algebraically manipulate the equation to end up with an equation with s on its own, on one side, making it the subject of the equation.We will start by looking at the terms in ...
DD
Answered by Divya D. • Maths tutor
64850 Views

Prove algebraically that 0.256565656... can be written as 127/495

Let x = 0.2565656...Then 10x = 2.565656.... and 1000x = 256.565656...So 1000x - 10x = 256.565656... - 2.565656... = 254990x = 254 x = 254/990 = 127/495
OT
Answered by Oliver T. • Maths tutor
16165 Views