Make s the subject of: v^2= u^2+2as

The aim of this question is to algebraically manipulate the equation to end up with an equation with s on its own, on one side, making it the subject of the equation.We will start by looking at the terms in the equation that are independent of s, this meaning that the variable isn't being multiplied or divided by 's'. In this equation we can see that both v^2 and u^2 are independent of s. So, as v^2 is already on the other side of 's', i.e. it is on the Left Hand Side, we shall start by subtracting u^2 from both sides of the equation. On the Left Hand Side, this leaves us with v^2 -u^2. On the Right Hand Side, we get u^2+2as-u^2, which leaves us with 2as, as the u^2 terms cancel out. Finally, to isolate s, we shall divide both sided of the equation by 2a, which, on the right hand side will leave us with 2as/2a = s, as 2a/2a=1. And dividing the left hand side by 2a will give us: (v^2 - u^2)/2a. Which means our final equation, with s as its subject will be: s= (v^2 - u^2)/2a.

DD
Answered by Divya D. Maths tutor

54715 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise and simplify (6x-42)/((x^2)-49)


How do you know which circle theorems to use when answering a question?


The line L1 is given by the Equation y =3x+5, and the line L2 is given by the Equation 4y-12x+16=0. Show that the lines L1 and L2 are Parallel


The Curve C has the equation 2x^2-11+13. The point Q lies on C such that the gradient of the normal to C at Q is -1/9. Find the x-co-ordinate of Q


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences