Find the roots of the following curve: y = 6x^2 - 4x.

The two terms in the quadratic equation share the factors 2 and x, so these can be brought outside the bracket as shown: y = 2x(3x-2). In order to solve for the roots (where the curve intercepts the x-axis), we must set y = 0 and hence satisfy the equation: 2x(3x-2) = 0. We can see that there are two possible solutions: 2x = 0 AND 3x-2 = 0. The first equation gives x = 0 and as for the second we can solve by adding 2 to both sides and then dividing by 3: 3x-2=0, 3x = 2, x = 2/3. So we have calculated the roots to be: x = 0 AND x = 2/3.

SK
Answered by Sam K. Maths tutor

2923 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Show that the lines y=3x+7 and 2y-6x=8 are parallel (not using a graphical method).


Simplify (m-7)(m+3)/6(m+3)


A ladder 5.5m long is leaning against a wall. the foot of the ladder is 1.7m away from the wall. how far up the wall does the ladder reach?


How do you write 36 as a product of its prime factors?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning