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Solve the simultaneous equations: 3x + 2y = 4 and 4x + 5y = 17

Step 1: multiply one or both equations so that the 2 equations have the same coefficient for either x or y (pick easier one) 5(3x + 2y) = 5(4) --> 15x + 10y = 20 AND 2(4x + 5y) = 2(17) --> 8x + 10y ...

RD
Answered by Rania D. Maths tutor
5283 Views

Solve algebraically the simultaneous equations x^2 + y^2 = 25 and y − 2x = 5 (5 marks)

First consider each equation separately and label them with a number. x2 + y2 = 25 (1) y - 2x = 5 (2)This question is difficult as it involves squa...

KS
Answered by Karisma S. Maths tutor
11832 Views

Factorise y^2 + 27y and simplify w^9/w^4

y2 + 27y = y(y + 27)To factorise you need to find the common factor between each part of the equation. In this case y is common between the different parts of the equation. Therefore you take y...

LM
Answered by Lucy M. Maths tutor
8608 Views

there are 11 sweets in a box four are soft centred and seven hard centred sweets two sweets are selected at random a)calculate the probability that both sweets are hard centred, b) one sweet is soft centred and one sweet is hard centred

a) First sweet you pick will be soft centred in 7 out of 11 cases, so the probability is 7/11when you are picking up a second sweet there are only 6 hard centred left and a total of 10, so the probability...

AT
Answered by Artem T. Maths tutor
5182 Views

give the values of x when 2x^2+5x-3=0

First we need to find two numbers that multiply to make ac and add to make b which are -6 and 5 in this case.The two numbers that do this are 6 and -1. Now we separate the 5x into 6x and -x. Putting this ...

SV
Answered by Sachin V. Maths tutor
2992 Views

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