Top answers

All subjects
All levels

Potassium Chlorate(VII) decomposes to produce Potassium Chloride and Oxygen. Using the following data calculate the enthalpy change of this decomposition: Enthalpy of formation(KClO4) = -430 kJ mol-1, Enthalpy of formation(KCl) = -440 kJ mol-1

Firstly the equation of this decomposition should be worked out to be the following
KClO4(s) --> KCl(s) + 2O2(g)
The enthalpy of formation has been given for both KClO<...

Answered by Chemistry tutor
15823 Views

Let N be an integer not divisible by 3. Prove N^2 = 3a + 1, where a is an integer

For N to be not divisible by 3, N can either be of the form 3k + 1 (1,4...) or 3k + 2 (2,5...), where k is an integer.
The proof can then be done by checking both 3k + 1 and 3k + 2 when N is squared...

Answered by Maths tutor
24423 Views

What should I include in a personal statement?

When writing your personal statement it can be tempting to include everything you have ever done and all the books you have read. However, due to the restricted length it is important to that you carefull...

2295 Views

How can the concept of opportunity cost be explained on different aspects of the economy?

Opportunity cost is the next best alternative choice that someone has. In an economy, it can be confronted by several actors; the government itself, consumers, or firms.
On an indiv...

SK
Answered by Stavria K. Economics tutor
1679 Views

how might a competitive inhibitor prevent the enzyme trypsin from working

inhibitor is a similar shape to the substrate
this means the inhibitor blocks the active site of the enzyme
the substrate cannot bind to the active site, so fewer enzyme substrate complexes can ...

Answered by Biology tutor
1855 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences