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a) Find the general solution to the differential equation: f(x)=y''-12y'-13y=8. b) Given that when x=0, y=0 and y'=1, find the particular solution to f(x).

First consider y''-12y'-13y=0.

Try: y=e^mx. This gives y'=me^mxand y''=m²e^mx.

Substituting into the differntial equation we get: m²e

Answered by Antonia P. • Further Mathematics tutor

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How do I prove that the differential of coshx is equal to sinhx?

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and when we square both side...

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Answered by Callum B. • Further Mathematics tutor

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