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Find the solution of 3^{4x} = 9^{(x-1)/2}.

First, recognise that 3^2 = 9. Recall the rule for multiplying indices, that (a^b)^c = a^{bc}. Then, substitute 3^2 in place of 9 to get 3^{4x} = (3^2)^{(x-1)/2}. Use the rule for multiplying indices, so tha...
CO
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f'(x) = 3x^2 - 5cos(3x) + 90. Find f(x) and f''(x).

Finding f(x) requires integrating the function f'(x), because f(x) is the integral of the given function f'(x). So {integralsymbol} f'(x) dx = {integralsymbol} (3x^2 - 5cos(3x) + 90) dx = x^3 - (5/3)sin(3x) ...
CO
2750 Views

How do I solve x^2 + x - 6 > 0 ?

This thing we have to solve is an inequality and the solution we are looking for is an entire range of real number, something like "every x between 1 and 2", for example. To do this we need to buil...
SG
12245 Views

Integrate xcos(x) with respect to x

Using LATEX (Logarithms, Algebra, Trigonometry, Exponential and Complex numbers) to determine which variable is du and which is dv/dx. This is decided by using the above acronym. For example in this question...
VP
3239 Views

How do you find the general solution of a second order differential equation?

Steps: Use the auxiliary equation on the equation given in the question Solve the resulting equation Identify the appropriate complementary function from the solutions Determine an appropriate particular int...
OD
3708 Views