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The line PQ is the diameter of a circle, where points P and Q have the coordinates (4,7) and (-8,3) respectively. Find the equation of the circle.

Start by using the formula d = sqrt((x2-x1)2+(y2-y1)2)Therefore, substituting in our coordinates from P and Q:Length PQ = sqrt((-8-4)...

MC
Answered by Matt C. Maths tutor
9729 Views

Prove that 2cot2x+tanx=cotx

2cot2x= 2(1/tan2x)= 2(1/(2tanx/1-tan2x))=2(1-tan2x)/2tanx= (1-tan2x)/tanx(1-tan2x)/tanx +tanx=(1-tan2x)/tanx +tan2x/tanx=1/tanx=cotx

AD
Answered by Alisa D. Maths tutor
19890 Views

Write x^2-4x+9 in the form (x-p)^2+q, where p and q are integers.

To complete this task we use a method called "Completing the square. For this we use a formula (a+b)^2=a^2+2ab+b^2.
Now we see that in the example we have a term x^2 so we put x^2=a^2 so we can ...

MS
Answered by Maria S. Maths tutor
5474 Views

P=(3a+5)/(4-a) Make a the subject

P=(3a+5)/(4-a)First of all we need Get rid of the denominator, we do this by multiplying both sides by (4-a)This leaves P(4-a)=3a+5 (as any term multiplied by the denominator leaves only the numerator)Th...

JS
Answered by Joshua S. Maths tutor
4042 Views

Rearrange v = u + at to make t the subject of the formula

t = (v - u) / a

GK
Answered by George K. Maths tutor
31011 Views

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