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The line l1 has equation y = −2x + 3. The line l2 is perpendicular to l1 and passes through the point (5, 6). (a) Find an equation for l2 in the form ax + by + c = 0, where a, b and c are integers.

The first thing to look at is l2 and l1 being perpendicular. This means the gradients of the two lines multiplied together = -1 . To determine the gradient a student could differentiate l1 but a slightly ...

RP
Answered by Roman Paul M. Maths tutor
16095 Views

I feel really nervous about time pressure in the exam, I don't think I'll finish

I used to struggle with this. The best way to get better at time management is to practice, practice, practice. A lot of exam practice isn't actually leanring the information, its exam technique. A few we...

LB
Answered by Laura B. Maths tutor
3248 Views

Explain the difference between the domain and range of a function.

The domain is the set of values you can put in for x. And the range is the set of vaules you get out of the function. On a graph f(x) against x, the difference in x value...

CP
Answered by Charlotte P. Maths tutor
4016 Views

Line Q goes through (0,5) and (4,7). Find the equation of Line Q in the form y = mx + c

M = Gradient M = (y2 - y1)/(x2 - x1) C = the 'y' intercept, where x = 0 Therefore, M = 2/4 = 1/2 = 0.5 y = 0.5x + 5

TD
Answered by Tutor105540 D. Maths tutor
4324 Views

PQRS is a parallelogram with P->Q=a and P->S=b. Find S->Q in terms of a and b. N is a point between S and Q, where SN:NQ is 3:2, find N->R

Vectors are special in that they have a direction as well as magnitude (size).

To get from S->Q you can go from S->P = -b and then P->Q =a so S->Q = -b + a = a

KB
Answered by Kristian B. Maths tutor
5037 Views

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