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Differentiate the following equation: y = 2(x^3) - 6x

Firstly we look at the term 2(x^3). The power of x (in this case 3) is multiplied by the factor of x (in this case 2) and the power is then reduced by 1. This means it is 2x3(x^{3-1}) which simplifies to ...

AW
Answered by Anna W. Maths tutor
3337 Views

Solve the equation (3x + 2)/(x - 1) + 3 = 4 (3 marks)

First, multiply all terms by (x - 1) to remove the quotient, and multiply out of the brackets: 3x + 2 + 3(x - 1) = 4(x - 1) >>> 3x + 2 + 3x - 3 = 4x - 4. Next, group all like terms on either side...

DP
Answered by Daniel P. Maths tutor
3528 Views

y = 3x^2 + 2x^(1/2) - 12 Find dy/dx

Firstly we divide up the equations into its three compenents based on the powers of the x values, giving us 3x^2, 2x^(1/2) and -12. Now one at a time, we multiply the coefficient by the power of x, and th...

SR
Answered by Sam R. Maths tutor
5459 Views

Solving 2tan(x) - 3sin(x) = 0 for -pi ≤ x < pi

The first step to answering this question is to get the equation in a simpler form. Aim to have it solely in terms of sin(x) and cos(x) with no fractional parts.                                           ...

BA
Answered by Benjamin A. Maths tutor
20335 Views

Take the polynomial p(x)=x^4+x^3+2x^2+4x-8, use the factor theorem to write p(x) as two linear factors and an irreducible quadratic. An irreducible quadratic is a quadratic that can not be factorised.

We must use the factor theorem since that is what the question asks. So we take p(x) and think about the factors of 8 we then evaluate it at x=1 to start, then move onto x=-1,2,-2 and so on. We see that i...

JC
Answered by Jordan C. Maths tutor
3691 Views

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