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Solve simultaneously. x^2+y^2 = 25 ; y - 3x = 13

y = 3x + 1310x^2 + 78x + 169 = 2510x^2 +78x +144 = 0(5x+24)(2x+6) = 0x = -24/5 or -3y = -7/5 or 16

BH
Answered by Ben H. Maths tutor
2477 Views

There are 5 blue counters and 5 red. x takes 2 counters out of the bag without replacing them. What is the probability x took 2 red counters.

5/10 * 4/9 = 20/90 = 2/9

BH
Answered by Ben H. Maths tutor
4170 Views

Find the value of (81)^(-1/2)

1/9

BH
Answered by Ben H. Maths tutor
5800 Views

3 1/2 - 2 1/3

Firstly we need to change each fraction into improper fractions. 7/2- 7/3then we need to give each fraction a common denominator. In this case we will use sixths. 21/6 - 14/6. Ans: 7/6

JT
Answered by Juliette T. Maths tutor
2526 Views

2(y+3) = 10. What is y?

So to start this question, we must multiply out the bracket as follows:2 x (y+3) = 10(2 x y) + (2 x 3) = 102y + 6 = 10Now we take away 6 from both sides of the equation:2y + 6 = 10 (NOW TAKE AWAY 6)2y = 4...

SE
Answered by Sophie E. Maths tutor
4609 Views

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