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A particle A of mass 0.1kg is moving at a speed of 1.5m/s to the right. It collides with a particle B of mass 0.3kg moving at a speed of 1.1m/s to the right. Calculate change in momentum of particle A if particle B has a speed of 1.4m/s after collision.

Momentum is conserved during the collision.Momentum = mass x velocityMomentum before = momentum after(mv)P1 + (mv)Q1 = (mv)P2 + (mv)Q2(0.1 x 1.5) + (0.3 x 1.1) ...

JS
Answered by Juliet S. Maths tutor
3598 Views

What is the area under the graph of (x^2)*sin(x) between 0 and pi

To solve this integral you need to use integration by parts twice. You separate the two term in the integral into x^2 and sin(x). You then multiple x^2 by the integral of sin(x) (-cos(x)) and apply the up...

KP
Answered by Khalil P. Maths tutor
4297 Views

A curve has parametric equations x = 1- cos(t), y = sin(t)sin(2t). Find dy/dx.

Here we have x(t) and y(t) which are both functions of t, but we want dy/dx, which doesn't involve t, we therefore need to use the chain rule. The chain rule tells us that: dy/dx = (dy/dt) x (dt/dx).y = s...

WM
Answered by William M. Maths tutor
6485 Views

Expand and simplify (x − 4)(2x + 3y)^2

following BIDMAS we start with the second expression by squaring it, i.e. (x-4)(2x + 3y)(2x + 3y). It is important we do it in the right order, otherwise we could get a wrong answer. We use the FOIL (Firs...

EA
Answered by Elsie A. Maths tutor
5164 Views

Express (4x)/((x^2) - 9) - (2)/(x + 3) as a single fraction in its simplest form (4 marks)

To do this we need to find a common denominator. We have an (x + 3) on the right hand side and a difference of two squares ((x^2)-9) on the left hand side. So factorising what looks more complicated is fi...

LN
Answered by Luke N. Maths tutor
4983 Views

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